Huobi Token - HT

Huobi Token HT price, market cap & charts

Live Huobi Token prices from all markets and HT coin market Capitalization. Stay up to date with the latest Huobi Token price movements and discussion. Check out our snapshot charts and see when there is an opportunity to buy or sell Huobi Token

Price

BTC 0.00039708
USD

4.19

Market Cap

USD

209,554,992

Change % (1H)

%

-0.09

Change % (24H)

%

2.34

Huobi Token (HT) Historical Price & Volume Charts

Huobi Token Wiki

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Huobi Token Key Financial Information

Mkt. CapUSD 209,554,992Volume 24HUSD 127,183,159
Mkt. Share0.07 %Available Supply50,000,200
Change % (1H)-0.09 %Max Supply0
Change % (24H)2.34 %Total Supply500,000,000
Change % (7D)4.64 %Proof
AlgorithmUpated: 42 minutes ago

Huobi Token Historical Data

DatePriceVolume

Huobi Token Videos

Counter-Intuitive Probability. Coin Flips To HH Versus HT Are Not The Same!
Should You Buy a $75 eBay Coin Grab Bag? See What I Got!

Huobi Token (HT) Reviews & Critics

What is the expected number of coin flips until you get two heads in a row (HH)? What is the expected number of coin flips until you get a heads followed by a ....

  • I just wrote some VBA code in Excel to simulate the game of coin flipping. My simulation program with say 10,000 tests (which takes only a few seconds to run) results in an average of about 6 tosses to get two consecutive Heads.
  • What is the difference between E(HH) and E(HH|T)?
  • This is very clear. Thanks for making this
  • I solved it a little differently:For HH:There is a 1/4 probability of HH on the first try (E=1); a 1/2 probability of the second spin being T, which "wastes" 2 rolls (E=2+E); and a 1/4 probability of second roll being H, further subdivided based on the third roll, with a 1/8 probability of success at E=2 (3 rolls total), and 1/8 probability of getting a T, "wasting" a total of 3 rolls (E=3+E), summed up thusly and solved for E, to get 5. This corresponds with the 6 from the video since the video is counting the final roll. I only count the first of the successful roll sequence to keep the equality P = 1/E.E = 1 (.25) + 2 ( .25 * .5 ) + (3+E)(.25*.5) + (2+E)*.5 = .25 + .25 + .375 + .125E + 1 + .5E = .875 + .125E + 1 + .5E = 1.875 + .625E = E.375E = 1.875E = 1.875 / .375 = 15 / 3 = 5For HT:Similarly, there is a 1/4 probability of HT on the first try (E=1); a 1/4 probability of the second spin otherwise being a T, "wasting" 2 spins (E=2+E); and a 1/2 probability of second roll being an H, further subdivided infinitely based on number of rolls to reach the T: 1/4 chance of E=2, 1/8 chance of E=3, 1/16 chance of E=4, et cetera, summed up thusly:E = 1(.25) + 2 (.5 * .5) + 3(.5*.5*.5) + 4(.5^4)+...+ (2+E)*.25x = 2(.5^2)+3(.5^3)+...+n(.5^n)2x = 2(.5)+3(.5^2)+...+n(.5^(n-1))2x - x = 2(.5) + .5^2 + .5^3 + .5^4 + ....5^nx = 1 + .5 = 1.5E = 1(.25) + 1.5 + (2+E)*.25 = 1.75 + .5 + .25E.75E = 2.25E = 2.25 / .75 = 9/3 = 3
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